2x^4-x^2+160=0

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Solution for 2x^4-x^2+160=0 equation:


Simplifying
2x4 + -1x2 + 160 = 0

Reorder the terms:
160 + -1x2 + 2x4 = 0

Solving
160 + -1x2 + 2x4 = 0

Solving for variable 'x'.

Begin completing the square.  Divide all terms by
2 the coefficient of the squared term: 

Divide each side by '2'.
80 + -0.5x2 + x4 = 0

Move the constant term to the right:

Add '-80' to each side of the equation.
80 + -0.5x2 + -80 + x4 = 0 + -80

Reorder the terms:
80 + -80 + -0.5x2 + x4 = 0 + -80

Combine like terms: 80 + -80 = 0
0 + -0.5x2 + x4 = 0 + -80
-0.5x2 + x4 = 0 + -80

Combine like terms: 0 + -80 = -80
-0.5x2 + x4 = -80

The x term is -0.5x2.  Take half its coefficient (-0.25).
Square it (0.0625) and add it to both sides.

Add '0.0625' to each side of the equation.
-0.5x2 + 0.0625 + x4 = -80 + 0.0625

Reorder the terms:
0.0625 + -0.5x2 + x4 = -80 + 0.0625

Combine like terms: -80 + 0.0625 = -79.9375
0.0625 + -0.5x2 + x4 = -79.9375

Factor a perfect square on the left side:
(x2 + -0.25)(x2 + -0.25) = -79.9375

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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